BHUJ AC SF EXP
The BHUJ AC SF EXP (22903) operates on Wed,fri,sun. It departs from BANDRA TERMINUS at 23:45 and arrives at BHUJ at 12:50. Covering a total distance of 838 km, the journey takes approximately 13 hours and 5 minutes, with halts at 7 intermediate stations.
| # | Station | Arrives | Departs | Halt | Distance | Day |
|---|---|---|---|---|---|---|
| 1 | BANDRA TERMINUSBDTS | --:-- | 23:45 | - | 0 km | Day 1 |
| 2 | BORIVALIBVI | 00:10 | 00:15 | 5m | 19 km | Day 2 |
| 3 | SURATST | 03:19 | 03:22 | 3m | 252 km | Day 2 |
| 4 | VADODARA JNBRC | 04:59 | 05:04 | 5m | 381 km | Day 2 |
| 5 | AHMEDABAD JNADI | 06:30 | 06:40 | 10m | 479 km | Day 2 |
| 6 | HALVADHVD | 08:54 | 08:56 | 2m | 641 km | Day 2 |
| 7 | SAMAKHIALI B GSIOB | 10:16 | 10:18 | 2m | 727 km | Day 2 |
| 8 | GANDHIDHAM BGGIMB | 11:20 | 11:40 | 20m | 780 km | Day 2 |
| 9 | BHUJBHUJ | 12:50 | --:-- | - | 838 km | Day 2 |
BDTS
Arrives
Halt
-Departs
BVI
Arrives
Halt
5mDeparts
ST
Arrives
Halt
3mDeparts
BRC
Arrives
Halt
5mDeparts
ADI
Arrives
Halt
10mDeparts
HVD
Arrives
Halt
2mDeparts
SIOB
Arrives
Halt
2mDeparts
GIMB
Arrives
Halt
20mDeparts
BHUJ
Arrives
Halt
-Departs
Frequently Asked Questions
What is the route and distance of the BHUJ AC SF EXP (22903)?
The BHUJ AC SF EXP (22903) runs between BANDRA TERMINUS (BDTS) and BHUJ (BHUJ), covering a total distance of 838 km.
On which days does the 22903 BHUJ AC SF EXP operate?
Train 22903 operates 3 days a week: Wed,fri,sun.
How long does the journey take on train 22903?
The total travel time for the BHUJ AC SF EXP from BANDRA TERMINUS to BHUJ is approximately 13 hours and 5 minutes, stopping at 7 intermediate halts.
What time does train 22903 depart and arrive?
Train 22903 departs from BANDRA TERMINUS at 23:45 and is scheduled to arrive at BHUJ at 12:50 on Day 2 of the journey.