1 | 17006 RXL HYB EXP | Sun | |
05:33 KML Kamtaul | 18:35 SC Secunderabad Jn | 37h 02m 1941 Km 52.4 km/hr | |
Distance Between Kamtaul and Secunderabad is 1942 kilometres. The below table lists distance in other units.
Distance | Unit |
---|---|
1942 | Kilometres |
1206.702482 | Miles |
1942000 | Meters |
194200000 | Centimeters |
2123790.62 | Yards |
6371391.28 | Feet |
76456734.2 | Inches |
Travel time from Kamtaul to Secunderabad is generally 36 hours and 46 minutes. Travel time for different trains are listed below.
Train Number | Time |
---|---|
17006 | 37 hours and 02 minutes |
According to the Indian Rail network distance between Kamtaul and Secunderabad Junction is 1942 kilometres. This distance is generally travelled in 36h 46m.
07006 Rxl-hyb Exp is the fastest train available from Kamtaul to Secunderabad. It takes only 36 hours and 46 minutes to complete the journey.
07006 Rxl-hyb Exp is the first train from Kamtaul to Secunderabad. It leaves Kamtaul at 05:29.
Night Kamtaul Secunderabad Trains Morning Kamtaul Secunderabad Trains KAMTAUL se SECUNDERABAD JN train